x+3(2x+4)=40^2

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Solution for x+3(2x+4)=40^2 equation: 



x+3(2x+4)=40^2

We move all terms to the left:

x+3(2x+4)-(40^2)=0

We add all the numbers together, and all the variables

x+3(2x+4)-1600=0

We multiply parentheses

x+6x+12-1600=0

We add all the numbers together, and all the variables

7x-1588=0

We move all terms containing x to the left, all other terms to the right

7x=1588

x=1588/7

x=226+6/7

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